Optimal. Leaf size=93 \[ \frac{(4 A-B) \tan ^3(e+f x)}{15 a^2 c^3 f}+\frac{(4 A-B) \tan (e+f x)}{5 a^2 c^3 f}+\frac{(A+B) \sec ^3(e+f x)}{5 a^2 f \left (c^3-c^3 \sin (e+f x)\right )} \]
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Rubi [A] time = 0.220292, antiderivative size = 93, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 36, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.083, Rules used = {2967, 2859, 3767} \[ \frac{(4 A-B) \tan ^3(e+f x)}{15 a^2 c^3 f}+\frac{(4 A-B) \tan (e+f x)}{5 a^2 c^3 f}+\frac{(A+B) \sec ^3(e+f x)}{5 a^2 f \left (c^3-c^3 \sin (e+f x)\right )} \]
Antiderivative was successfully verified.
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Rule 2967
Rule 2859
Rule 3767
Rubi steps
\begin{align*} \int \frac{A+B \sin (e+f x)}{(a+a \sin (e+f x))^2 (c-c \sin (e+f x))^3} \, dx &=\frac{\int \frac{\sec ^4(e+f x) (A+B \sin (e+f x))}{c-c \sin (e+f x)} \, dx}{a^2 c^2}\\ &=\frac{(A+B) \sec ^3(e+f x)}{5 a^2 f \left (c^3-c^3 \sin (e+f x)\right )}+\frac{(4 A-B) \int \sec ^4(e+f x) \, dx}{5 a^2 c^3}\\ &=\frac{(A+B) \sec ^3(e+f x)}{5 a^2 f \left (c^3-c^3 \sin (e+f x)\right )}-\frac{(4 A-B) \operatorname{Subst}\left (\int \left (1+x^2\right ) \, dx,x,-\tan (e+f x)\right )}{5 a^2 c^3 f}\\ &=\frac{(A+B) \sec ^3(e+f x)}{5 a^2 f \left (c^3-c^3 \sin (e+f x)\right )}+\frac{(4 A-B) \tan (e+f x)}{5 a^2 c^3 f}+\frac{(4 A-B) \tan ^3(e+f x)}{15 a^2 c^3 f}\\ \end{align*}
Mathematica [B] time = 0.960834, size = 237, normalized size = 2.55 \[ \frac{\left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right ) \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right ) (54 (A+B) \cos (e+f x)-32 (4 A-B) \cos (2 (e+f x))-384 A \sin (e+f x)-18 A \sin (2 (e+f x))-128 A \sin (3 (e+f x))-9 A \sin (4 (e+f x))+18 A \cos (3 (e+f x))-64 A \cos (4 (e+f x))+96 B \sin (e+f x)-18 B \sin (2 (e+f x))+32 B \sin (3 (e+f x))-9 B \sin (4 (e+f x))+18 B \cos (3 (e+f x))+16 B \cos (4 (e+f x))-240 B)}{960 a^2 c^3 f (\sin (e+f x)-1)^3 (\sin (e+f x)+1)^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.095, size = 183, normalized size = 2. \begin{align*} 2\,{\frac{1}{{a}^{2}f{c}^{3}} \left ( -1/5\,{\frac{A+B}{ \left ( \tan \left ( 1/2\,fx+e/2 \right ) -1 \right ) ^{5}}}-1/4\,{\frac{2\,A+2\,B}{ \left ( \tan \left ( 1/2\,fx+e/2 \right ) -1 \right ) ^{4}}}-1/2\,{\frac{3/2\,A+B}{ \left ( \tan \left ( 1/2\,fx+e/2 \right ) -1 \right ) ^{2}}}-1/3\,{\frac{5/2\,A+2\,B}{ \left ( \tan \left ( 1/2\,fx+e/2 \right ) -1 \right ) ^{3}}}-{\frac{1}{\tan \left ( 1/2\,fx+e/2 \right ) -1} \left ({\frac{11\,A}{16}}+3/16\,B \right ) }-1/2\,{\frac{-A/4+B/4}{ \left ( \tan \left ( 1/2\,fx+e/2 \right ) +1 \right ) ^{2}}}-1/3\,{\frac{A/4-B/4}{ \left ( \tan \left ( 1/2\,fx+e/2 \right ) +1 \right ) ^{3}}}-{\frac{1}{\tan \left ( 1/2\,fx+e/2 \right ) +1} \left ({\frac{5\,A}{16}}-3/16\,B \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.07258, size = 879, normalized size = 9.45 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.62225, size = 262, normalized size = 2.82 \begin{align*} -\frac{2 \,{\left (4 \, A - B\right )} \cos \left (f x + e\right )^{4} -{\left (4 \, A - B\right )} \cos \left (f x + e\right )^{2} +{\left (2 \,{\left (4 \, A - B\right )} \cos \left (f x + e\right )^{2} + 4 \, A - B\right )} \sin \left (f x + e\right ) - A + 4 \, B}{15 \,{\left (a^{2} c^{3} f \cos \left (f x + e\right )^{3} \sin \left (f x + e\right ) - a^{2} c^{3} f \cos \left (f x + e\right )^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.23233, size = 317, normalized size = 3.41 \begin{align*} -\frac{\frac{5 \,{\left (15 \, A \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{2} - 9 \, B \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{2} + 24 \, A \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) - 12 \, B \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) + 13 \, A - 7 \, B\right )}}{a^{2} c^{3}{\left (\tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) + 1\right )}^{3}} + \frac{165 \, A \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{4} + 45 \, B \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{4} - 480 \, A \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{3} - 60 \, B \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{3} + 650 \, A \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{2} + 70 \, B \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{2} - 400 \, A \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) - 20 \, B \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) + 113 \, A + 13 \, B}{a^{2} c^{3}{\left (\tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) - 1\right )}^{5}}}{120 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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